Whole genome analysis for QTL/association enrichment
Running...
Version: Enrich S: beta v0.8
Data:
Number of reproductive hormone level traits:
3
Number of QTL / associations found:
306
Number of chromosomes where QTL / associations are found:
12
Chi-squared (χ2) test: are reproductive hormone level traits over-represented on some chromosomes?
Chromosomes
Total χ2
df
p-values
FDR *
Size of χ2
Chromosome X
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 2
36.02940
11
0.0001673413
1.673413e-04
Chromosome 3
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 5
7983.55881
11
9e-41
1.080000e-39
Chromosome 6
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 13
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 15
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 17
64.97058
11
1.091446e-09
1.190668e-09
Chromosome 21
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 26
70.61766
11
9.32135e-11
1.242847e-10
Chromosome 28
64.97058
11
1.091446e-09
1.190668e-09
Chromosome 29
70.61766
11
9.32135e-11
1.242847e-10
Chi-squared (χ2) test: Which of the 3 reproductive hormone level traits are over-represented in the QTLdb
Traits
Total χ2
df
p-values
FDR *
Size of χ2
Follicle stimulating hormone level
0.06995
2
0.9656296
9.656296e-01
Inhibin level
4.47354
2
0.1068029
1.602043e-01
Luteinizing hormone level
270.4
2
1.920375e-59
5.761125e-59
Correlations found between some of these traits for your reference
No correlation data found on these traits
Overall Test
Data
Chi'Square Test
Fisher's Exact Test
Number of chrom.:
12
χ2
=
8714.470650
Number of traits:
3
df
=
22
Number of QTLs:
306
p-value
=
0
FOOT NOTE: * : FDR is short for "false
discovery rate", representing the expected proportion of type I errors. A type I
error is where you incorrectly reject the null hypothesis, i.e. you get a false
positive. It's statistical definition is FDR = E(V/R | R > 0) P(R > 0), where
V = Number of Type I errors (false positives); R = Number of rejected hypotheses.
Benjamini–Hochberg procedure is a practical way to estimate FDR.
Running...
